\documentclass{article}%
\usepackage{graphicx}
\usepackage{amsmath}%
\setcounter{MaxMatrixCols}{30}%
\usepackage{amsfonts}%
\usepackage{amssymb}
%TCIDATA{OutputFilter=latex2.dll}
%TCIDATA{Version=5.50.0.2953}
%TCIDATA{CSTFile=LaTeX article (bright).cst}
%TCIDATA{Created=Tue May 11 21:56:22 2004}
%TCIDATA{LastRevised=Wednesday, June 11, 2008 10:11:26}
%TCIDATA{<META NAME="GraphicsSave" CONTENT="32">}
%TCIDATA{<META NAME="SaveForMode" CONTENT="1">}
%TCIDATA{BibliographyScheme=Manual}
%TCIDATA{<META NAME="DocumentShell" CONTENT="General\Blank Document">}
%BeginMSIPreambleData
\providecommand{\U}[1]{\protect\rule{.1in}{.1in}}
%EndMSIPreambleData
\newtheorem{theorem}{Theorem}
\newtheorem{acknowledgement}[theorem]{Acknowledgement}
\newtheorem{algorithm}[theorem]{Algorithm}
\newtheorem{axiom}[theorem]{Axiom}
\newtheorem{case}[theorem]{Case}
\newtheorem{claim}[theorem]{Claim}
\newtheorem{conclusion}[theorem]{Conclusion}
\newtheorem{condition}[theorem]{Condition}
\newtheorem{conjecture}[theorem]{Conjecture}
\newtheorem{corollary}[theorem]{Corollary}
\newtheorem{criterion}[theorem]{Criterion}
\newtheorem{definition}[theorem]{Definition}
\newtheorem{example}[theorem]{Example}
\newtheorem{exercise}[theorem]{Exercise}
\newtheorem{lemma}[theorem]{Lemma}
\newtheorem{notation}[theorem]{Notation}
\newtheorem{problem}[theorem]{Problem}
\newtheorem{proposition}[theorem]{Proposition}
\newtheorem{remark}[theorem]{Remark}
\newtheorem{solution}[theorem]{Solution}
\newtheorem{summary}[theorem]{Summary}
\newenvironment{proof}[1][Proof]{\textbf{#1.} }{\ \rule{0.5em}{0.5em}}
\begin{document}
Si \ $f(x)=\left\vert \dfrac{x^{2}-9}{x-3}\right\vert $ el valor de $f(a)$
es:\medskip\newline a)$f(a)=\left\vert a+3\right\vert \qquad$b)$f(a)=a-3\qquad
$c)$f(a)=a+3\qquad$d)$f(a)=\left\vert a-3\right\vert $

Si \ $f(x)=\left\vert \dfrac{x-9}{x-3}\right\vert $ el valor de $f(a)$
es:\medskip\newline\qquad a) $f(a)=\left\vert \dfrac{a-9}{a-3}\right\vert
\qquad$b) $f(a)=a-3\qquad$c) $f(a)=\dfrac{a-9}{a-3}\qquad$d) $f(a)=\left\vert
a-9\right\vert $

Si \ $f(x)=\left\vert \dfrac{x^{2}-25}{x+5}\right\vert $ el valor de $f(a)$
es:\medskip\newline\qquad a) $f(a)=\left\vert a-5\right\vert \qquad$b)
$f(a)=a-5\qquad$c) $f(a)=\dfrac{a-5}{a+5}\qquad$d) $f(a)=\left\vert
a+5\right\vert $

Si \ $f(x)=\left\vert \dfrac{x^{2}-4}{x+2}\right\vert $ el valor de $f(a)$
es:\medskip\newline\qquad a) $f(a)=\left\vert a-2\right\vert \qquad$b)
$f(a)=a-2\qquad$c) $f(a)=\dfrac{a-2}{a+2}\qquad$d) $f(a)=\left\vert
a+2\right\vert $

Si \ $f(x)=\left\vert \dfrac{x^{2}-16}{x-4}\right\vert $ el valor de $f(a)$
es:\medskip\newline\qquad a) $f(a)=\left\vert a+4\right\vert \qquad$b)
$f(a)=a-4\qquad$c) $f(a)=\dfrac{a-4}{a+4}\qquad$d) $f(a)=\left\vert
a-4\right\vert $

Si $f(x)=\dfrac{x^{3}}{\sqrt{x+1}}$ el valor de $f(a)$ es:\qquad
\medskip\newline\qquad a) $f(a)=\dfrac{a^{3}}{\sqrt{a+1}}$\qquad b)
$f(a)=\dfrac{a}{a-1}$\qquad c) $f(a)=0$\qquad d) $f(a)=a$

Si $f(x)=\left\vert x-3\right\vert $ el valor de $f(a)$ es:\medskip
\newline\qquad a) $f(a)=\left\vert a-3\right\vert $\qquad b) $f(a)=\left\vert
a-5\right\vert $\qquad c) $f(a)=1$\qquad d) $f(a)=0$

Si $f(x)=\dfrac{x+1}{3x+3}$ el valor de $f(a)$ es:\medskip\newline\qquad a)
$f(a)=\dfrac{a+1}{3a+3}$ \qquad b) $f(a)=1\qquad$c) $f(a)=\dfrac{a}{2}$\qquad
d) $f(a)=a$

Si $f(x)=\dfrac{\left\vert x-5\right\vert }{x+2}$ el valor de $f(a)$
es:\medskip\newline\qquad a) $f(a)=\dfrac{\left\vert a-5\right\vert }{a+2}%
$\qquad b) $f(a)=\dfrac{a-5}{a+3}$\qquad c) $f(a)=a$\qquad d) $f(a)=0$

Si $f(x)=\left\vert \dfrac{x+7}{x-3}\right\vert $ el valor de $f(a)$
es:\medskip\qquad\newline\qquad a) $f(a)=\left\vert \dfrac{a+7}{a-3}%
\right\vert $\qquad b) $f(a)=a$\qquad c) $f(a)=\dfrac{a+7}{a+3}$\qquad d)
$f(a)=1$

Si $f(x)=\dfrac{x^{2}+5}{x+1}$ el valor de $f(a)$ es:\newline\qquad a)
$f(a)=\dfrac{a^{2}+5}{a+1}$\qquad b) $f(a)=\dfrac{a^{2}}{2}$\qquad c)
$f(a)=a$\qquad d) $f(a)=0$

Si $f(x)=\left\vert x+2\right\vert -2x$ el valor de $f(a)$ es:\medskip
\newline\qquad a) $f(a)=\left\vert a+2\right\vert -2a$\qquad b) $f(a)=1$\qquad
c) $f(a)=a$\qquad d) $f(a)=\left\vert a+1\right\vert $

Si $f(x)=\dfrac{1}{\left\vert x+2\right\vert }-2$ el valor de $f(a)$
es:\medskip\newline\qquad a) $f(a)=\dfrac{1}{\left\vert a+2\right\vert }%
-2$\qquad b) $f(a)=a$\qquad c) $f(a)=1$\qquad d) $f(a)=\dfrac{-1}{\left\vert
a+2\right\vert }$

Si $f(x)=\dfrac{3x}{2x+1}$ el valor de $f(a)$ es:\medskip\newline\qquad a)
$f(a)=\dfrac{3a}{2a+1}$\qquad b) $f(a)=0$\qquad c) $f(a)=\dfrac{a}{a+1}$\qquad
d) $f(a)=a$

Si $f(x)=\dfrac{5x+1}{\left\vert x-5\right\vert }$ el valor de $f(a)$
es:\medskip\newline\qquad a) $f(a)=\dfrac{5a+1}{\left\vert a-5\right\vert }%
$\qquad b) $f(a)=\left\vert a-2\right\vert $\qquad c) $f(a)=0$\qquad d)
$f(a)=a$


\end{document}